如何选择正确的EMRAX电机类型？

一。首先你需要知道什么转速和扭矩你将需要你的应用。

要找到合适的EMRAX电机，应检查技术数据中列出的最大电机转速

每个EMRAX电机的表。确保考虑扭矩/转速图和控制器

提供足够大的相电流，从电机获得足够大的扭矩。

2。在技术数据表中，您可以找到每个EMRAX电机的特定负载速度（RPM/1Vdc）。与

这个数据你可以计算什么电池电压（直流）你需要达到理想的转速在负载

申请。

*在磁场减弱（MFW）的情况下，可以获得更高的转速。你可以用磁场

转矩最大时的弱化模式。在磁场中稍微削弱转矩

降低，但转速上升，因此功率保持不变（看下面的方程式）。

可在控制器软件中设置磁场减弱。EMRAX电机有10极对，

因此，建议将磁场减弱5-10%，以达到最佳效果

表演。当磁场减弱的百分比越高，电机的运行速度就越快

效率，在80%MFW时仅下降1%到2%。我们只推荐短时间的MFW（很少

如果电机功率足够，则最小），因为电机和

控制器。

三。现在你可以用这个公式计算出功率：

𝑷 [𝒌𝑾] = 𝒏 [𝑹𝑷𝑴] ∗ 𝑴𝒕 [𝑵𝒎] / 𝟗𝟓𝟓𝟎

在较低的转速（电机旋转）下，在相同的扭矩下，可以期望较低的电机功率。在更高的位置

电机转速，你可以期望更高的电机功率在相同的扭矩。

Mt……扭矩[Nm]

P、 ……功率[kW]

n、 ……电机转速[RPM]

如果您需要更高的功率，我们建议您增加电池电压（Vdc），而不是

增加电机电流-因为需要更大直径的电缆，因此

体重更重。如果需要更高的电机转速（RPM），最好使用高压电机。

四。228 MV示例：

客户负载时蓄电池电压为365伏直流电。

228 MV电机在负载时可输出11 RPM/1Vdc，在空载应用时可输出14 RPM/1Vdc。

在这种情况下，电机的速度为：365[𝑉𝑑𝑐]*11=4015[𝑅𝑃𝑀]。

228MV电机的比转矩为0.75Nm/1Arms。

因此，在来自Bamocar D3的180臂电流下，电机功率为：

4015[𝑅𝑃𝑀]*135𝑁𝑚÷9550=56,7[𝑘𝑊]这是您可以期望的最大值

控制器。如果你想要更多的电力，你需要更高的直流电压，以获得更高的转速和更高的电机

当前。你需要应用340臂峰值（这给应用230至240牛米的扭矩与EMRAX 228毫伏

尺寸）。所以，如果你能增加电流，你将接近100千瓦。但我们建议你

增加电池电压以获得更高的转速，从而获得更高的功率。在这种情况下你可以

使用EMRAX 228高压。


How to choose the correct EMRAX motor type for your application?

1. First you need to know what RPM and torque you will need for your application.
To find the suitable EMRAX motor you should check the maximal motor RPM listed in Technical data
table for each EMRAX motor. Make sure, to consider the Torque/RPM graph and that the controller
gives enough high phase current to get enough high torque from the motor.
2. In the Technical Data table, you can find Specific load speed (RPM/1Vdc) for each EMRAX motor. With
this data you can calculate what battery voltage (Vdc) you need to achieve desired RPM at load
application.
*It is possible to achieve higher RPM with magnetic field weakening (MFW). You can use magnetic field
weakening mode when torque is at maximal value. At magnetic field weakening the torque slightly
decreases, but the RPM rises and consequently the power stays the same (look at the equation below).
Magnetic field weakening can be set in the controller software. EMRAX motors have 10 pole pairs,
therefore it is recommended to weaken the magnetic field for 5 to 10 % to achieve the best
performances. With higher % of magnetic field weakening the motor can run faster with very good
efficiency, which drops only for 1% to 2% at 80% MFW. We recommend MFW only for a short time (few
min in case full motor power), because of a very high phase current between the motor and the
controller.
3. Now you can calculate the power, using this equation:
𝑷 [𝒌𝑾] = 𝒏 [𝑹𝑷𝑴] ∗ 𝑴𝒕 [𝑵𝒎] / 𝟗𝟓𝟓𝟎
At a lower RPM (motor rotation), you can expect lower motor power at the same torque. At a higher
motor speed, you can expect higher motor power at the same torque.
Mt……torque [Nm]
P………power [kW]
n………motor rotation [RPM]
In case you need higher power, we recommend you increasing battery voltage (Vdc) instead of
increasing motor current – because cables with bigger diameter are needed and consequently the
weight is bigger. It is better to use a high voltage motor if you need higher motor speed (RPM).
4. Example for 228 MV:
Customer has battery voltage 365 Vdc at load.
228 MV motor can deliver 11 RPM/1Vdc at load to 14 RPM/1Vdc at no load application.
In this case the motor the speed is: 365 [𝑉𝑑𝑐] ∗ 11 = 4015 [𝑅𝑃𝑀].
Specific torque for 228MV motor is 0,75Nm/1Arms.
Therefore at 180 Arms of the current from Bamocar D3, the motor power is:
4015 [𝑅𝑃𝑀] ∗ 135 𝑁𝑚 ÷ 9550 = 56,7[𝑘𝑊] This is the maximum which you can expect with this
controller. If you want more power, you need higher dc voltage to get higher RPM and higher motor
current. You need app 340 Arms peak (which gives app 230 to 240 Nm of torque with EMRAX 228 MV
size). So, if you can increase the current you will be closer to 100 kW. But we recommended that you
increase the battery voltage to get higher RPM and consequently higher power. In this case you can

use EMRAX 228 HV.